[Leet Code] Maximum Depth Of Binary Tree
2 min readJan 30, 2021
Leetcode: https://leetcode.com/problems/maximum-depth-of-binary-tree/
Problem:
Given the root
of a binary tree, return its maximum depth.
A binary tree’s maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
Example 1:
Input: root = [3,9,20,null,null,15,7]
Output: 3
Example 2:
Input: root = [1,null,2]
Output: 2
Example 3:
Input: root = []
Output: 0
Example 4:
Input: root = [0]
Output: 1
Solution:
# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution(object):
def maxDepth(self, root):
"""
:type root: TreeNode
:rtype: int
"""
if root:
stack = [root]
elements = [[root.val]]
self.helper(root, stack, elements)
return len(elements)
else:
return 0
def helper(self, root, stack, elements):
while(len(stack) > 0):
length = len(stack)
values = []
for i in range(length):
node = stack.pop(0)
if node.left:
values.append(node.left.val)
stack.append(node.left)
if node.right:
values.append(node.right.val)
stack.append(node.right)
if values != []:
elements.append(values)