# [Leet Code] Relative Ranks

Problem:

You are given an integer array `score` of size `n`, where `score[i]` is the score of the `ith` athlete in a competition. All the scores are guaranteed to be unique.

The athletes are placed based on their scores, where the `1st` place athlete has the highest score, the `2nd` place athlete has the `2nd` highest score, and so on. The placement of each athlete determines their rank:

• The `1st` place athlete's rank is `"Gold Medal"`.
• The `2nd` place athlete's rank is `"Silver Medal"`.
• The `3rd` place athlete's rank is `"Bronze Medal"`.
• For the `4th` place to the `nth` place athlete, their rank is their placement number (i.e., the `xth` place athlete's rank is `"x"`).

Return an array `answer` of size `n` where `answer[i]` is the rank of the `ith` athlete.

Example 1:

`Input: score = [5,4,3,2,1]Output: ["Gold Medal","Silver Medal","Bronze Medal","4","5"]Explanation: The placements are [1st, 2nd, 3rd, 4th, 5th].`

Example 2:

`Input: score = [10,3,8,9,4]Output: ["Gold Medal","5","Bronze Medal","Silver Medal","4"]Explanation: The placements are [1st, 5th, 3rd, 2nd, 4th].`

Constraints:

• `n == score.length`
• `1 <= n <= 104`
• `0 <= score[i] <= 106`
• All the values in `score` are unique.

Solution:

`class Solution(object):    def findRelativeRanks(self, score):        """        :type score: List[int]        :rtype: List[str]        """        sorted_array = sorted(score, reverse=True)        result_list = []        for i in score:            result = sorted_array.index(i) + 1            if result == 1:                 result_list.append("Gold Medal")            elif result == 2:                result_list.append("Silver Medal")            elif result == 3:                 result_list.append("Bronze Medal")            else:                result_list.append(str(result))        return result_list`

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