[Leet Code] XOR Operation in an Array

Leet Code: https://leetcode.com/problems/xor-operation-in-an-array/

Problem:

Given an integer n and an integer start.

Define an array nums where nums[i] = start + 2*i (0-indexed) and n == nums.length.

Return the bitwise XOR of all elements of nums.

Example 1:

Input: n = 5, start = 0
Output: 8
Explanation: Array nums is equal to [0, 2, 4, 6, 8] where (0 ^ 2 ^ 4 ^ 6 ^ 8) = 8.
Where "^" corresponds to bitwise XOR operator.

Example 2:

Input: n = 4, start = 3
Output: 8
Explanation: Array nums is equal to [3, 5, 7, 9] where (3 ^ 5 ^ 7 ^ 9) = 8.

Example 3:

Input: n = 1, start = 7
Output: 7

Example 4:

Input: n = 10, start = 5
Output: 2

Solution:

class Solution(object):
    def xorOperation(self, n, start):
        """
        :type n: int
        :type start: int
        :rtype: int
        """
        bitwise = 0
        for i in range(n):
            bitwise ^= (start + 2*i)
        return bitwise

Explanation: We can create a for loop that will iterate to the number specified n then we keep a running total of bitwise and do XOR start + 2*i like specified in the problem.